Balance this reaction: underline ( )NH_(3)+underline ( )H_(2)SO_(4)arrow underline ( )(NH_(4))_(2)SO_(4)? 211 1,22 21,2

To balance the chemical equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.<br /><br />Given equation: $\underline {\quad }NH_{3}+\underline {\quad }H_{2}SO_{4}\rightarrow \underline {\quad }(NH_{4})_{2}SO_{4}$<br /><br />Step 1: Balance the nitrogen atoms.<br />There is 1 nitrogen atom on the left side and 2 nitrogen atoms on the right side. To balance the nitrogen atoms, we need to put a coefficient of 2 in front of NH3.<br /><br />$2NH_{3}+H_{2}SO_{4}\rightarrow (NH_{4})_{2}SO_{4}$<br /><br />Step 2: Balance the hydrogen atoms.<br />There are 6 hydrogen atoms on the left side and 8 hydrogen atoms on the right side. To balance the hydrogen atoms, we need to put a coefficient of 1 in front of H2SO4.<br /><br />$2NH_{3}+H_{2}SO_{4}\rightarrow (NH_{4})_{2}SO_{4}$<br /><br />Step 3: Balance the sulfur atoms.<br />There is 1 sulfur atom on the left side and 1 sulfur atom on the right side. The sulfur atoms are already balanced.<br /><br />$2NH_{3}+H_{2}SO_{4}\rightarrow (NH_{4})_{2}SO_{4}$<br /><br />The balanced chemical equation is: $2NH_{3}+H_{2}SO_{4}\rightarrow (NH_{4})_{2}SO_{4}$<br /><br />Therefore, the correct answer is: 2, 1, 1.