A potter's wheel moves from rest to an angular speed of 0.10rev/s in 31.5 s. Assuming constant angular acceleration, what is its angular acceleration in rad/s^2 Answer in units of rad/s^2 Answer in units of rad/s^2

To find the angular acceleration, we can use the formula:<br /><br />Angular acceleration = (Final angular velocity - Initial angular velocity) / Time<br /><br />First, we need to convert the final angular velocity from rev/s to rad/s:<br /><br />Final angular velocity = 0.10 rev/s * 2π rad/rev = 0.20π rad/s<br /><br />Now we can calculate the angular acceleration:<br /><br />Angular acceleration = (0.20π rad/s - 0 rad/s) / 31.5 s<br />Angular acceleration = 0.20π / 31.5 rad/s²<br />Angular acceleration ≈ 0.020 rad/s²<br /><br />Therefore, the angular acceleration of the potter's wheel is approximately 0.020 rad/s².