7. How many moles of HCl is needed to produce 46 moles of ZnCl_(2)

To determine how many moles of HCl are needed to produce 46 moles of \( ZnCl_2 \), we need to consider the balanced chemical equation for the reaction between zinc (Zn) and hydrochloric acid (HCl).<br /><br />The balanced chemical equation is:<br />\[ Zn + 2HCl \rightarrow ZnCl_2 + H_2 \]<br /><br />From the equation, we see that 1 mole of \( ZnCl_2 \) is produced from 2 moles of \( HCl \).<br /><br />Given that we need to produce 46 moles of \( ZnCl_2 \), we can use the stoichiometric ratio to find the required moles of \( HCl \):<br /><br />\[ \text{Moles of } HCl = 46 \text{ moles of } ZnCl_2 \times \frac{2 \text{ moles of } HCl}{1 \text{ mole of } ZnCl_2} \]<br /><br />\[ \text{Moles of } HCl = 92 \text{ moles} \]<br /><br />Therefore, 92 moles of \( HCl \) are needed to produce 46 moles of \( ZnCl_2 \).