If you react 5 moles of AlCl_(3) with the required amount of Ca, how many moles of Al would be produced? 3Ca+2AlCl_(3)arrow 3CaCl_(2)+2Al 7.5 moles of Al 5 moles of Al 15 moles of Al 10 moles of Al

The balanced chemical equation given is:<br />\[ 3Ca + 2AlCl_{3} \rightarrow 3CaCl_{2} + 2Al \]<br />From the equation, we can see that 2 moles of \( AlCl_{3} \) produce 2 moles of Al. Therefore, if we react 5 moles of \( AlCl_{3} \), we would produce 5 moles of Al. Hence, the correct answer is 5 moles of Al.