If I dilute 250 mL of 0.10 M lithlum acetate solution to a volume of 750 mL, what will be the concentratic 0.02 M 0.033 m 19 M 30 M

## Step 1<br />The problem involves the concept of dilution in chemistry. The concentration of a solution is determined by the amount of solute divided by the volume of the solution. When a solution is diluted, the amount of solute remains constant, but the volume of the solution increases. This means that the concentration of the solution decreases.<br /><br />## Step 2<br />The formula for dilution is given as:<br />### \(C1V1 = C2V2\)<br />where \(C1\) is the initial concentration, \(V1\) is the initial volume, \(C2\) is the final concentration, and \(V2\) is the final volume.<br /><br />## Step 3<br />In this problem, we are given \(C1 = 0.10M\), \(V1 = 250mL\), and \(V2 = 750mL\). We are asked to find \(C2\), the final concentration.<br /><br />## Step 4<br />We can rearrange the dilution formula to solve for \(C2\):<br />### \(C2 = \frac{C1V1}{V2}\)<br /><br />## Step 5<br />Substituting the given values into the formula, we get:<br />### \(C2 = \frac{0.10M \times 250mL}{750mL}\)<br /><br />## Step 6<br />Calculating the above expression, we find that \(C2 = 0.033M\).