6PaCl5+5Gd3N2-15GdCl2+5Pa3N5 How many moles of Pa3N5 do I get from 6.4 mol PaCl5? 4.24 5.33 6.69 7.68

To determine the number of moles of \( \text{Pa}_3\text{N}_5 \) produced from 6.4 moles of \( \text{PaCl}_5 \), we need to use the stoichiometric coefficients from the balanced chemical equation:<br /><br />\[ 6\text{PaCl}_5 + 5\text{Gd}_3\text{N}_2 \rightarrow 15\text{GdCl}_2 + 5\text{Pa}_3\text{N}_5 \]<br /><br />From the equation, we see that 6 moles of \( \text{PaCl}_5 \) produce 5 moles of \( \text{Pa}_3\text{N}_5 \).<br /><br />We can set up a proportion to find out how many moles of \( \text{Pa}_3\text{N}_5 \) are produced from 6.4 moles of \( \text{PaCl}_5 \):<br /><br />\[ \frac{6 \text{ moles of } \text{PaCl}_5}{5 \text{ moles of } \text{Pa}_3\text{N}_5} = \frac{6.4 \text{ moles of } \text{PaCl}_5}{x \text{ moles of } \text{Pa}_3\text{N}_5} \]<br /><br />Now, solve for \( x \):<br /><br />\[ x = \frac{6.4 \times 5}{6} \]<br /><br />\[ x = \frac{32}{6} \]<br /><br />\[ x = 5.33 \]<br /><br />Therefore, the number of moles of \( \text{Pa}_3\text{N}_5 \) produced from 6.4 moles of \( \text{PaCl}_5 \) is 5.33 moles. The correct answer is 5.33.