If 19,000 electrons are removed from a neutral object.What charge has been removed. (Charge of electron 1.6times 10^-19) -1.9E5 1.74 E14 -1.74E14 1.9E5 -3.04E-15 3.04E-15

To find the charge removed when 19,000 electrons are removed from a neutral object, we need to multiply the number of electrons by the charge of each electron.<br /><br />Given:<br />- Number of electrons removed = 19,000<br />- Charge of each electron = $1.6\times 10^{-19}$ C<br /><br />The total charge removed can be calculated as:<br />\[ \text{Total charge} = \text{Number of electrons} \times \text{Charge of each electron} \]<br />\[ \text{Total charge} = 19000 \times 1.6\times 10^{-19} \]<br />\[ \text{Total charge} = 3.04\times 10^{-15} \, \text{C} \]<br /><br />Since electrons have a negative charge, the charge removed will also be negative.<br /><br />Therefore, the charge removed is:<br />\[ -3.04\times 10^{-15} \, \text{C} \]<br /><br />So, the correct answer is:<br />\[ -3.04E-15 \]