Water has a specific heat capacity of 4.18J/g^circ C How much heat is required to raise 100g of water by 10^circ C 41.8 J 418 J 4180 4180 J

To calculate the amount of heat required to raise the temperature of a substance, we can use the formula:<br /><br />\[ Q = mc\Delta T \]<br /><br />where:<br />- \( Q \) is the heat energy (in joules)<br />- \( m \) is the mass of the substance (in grams)<br />- \( c \) is the specific heat capacity (in \( J/g^{\circ}C \))<br />- \( \Delta T \) is the change in temperature (in \( ^{\circ}C \))<br /><br />Given:<br />- Specific heat capacity of water, \( c = 4.18 \, J/g^{\circ}C \)<br />- Mass of water, \( m = 100 \, g \)<br />- Change in temperature, \( \Delta T = 10^{\circ}C \)<br /><br />Now, plug these values into the formula:<br /><br />\[ Q = 100 \, g \times 4.18 \, J/g^{\circ}C \times 10^{\circ}C \]<br /><br />\[ Q = 4180 \, J \]<br /><br />Therefore, the correct answer is:<br /><br />\[ \boxed{4180 \, J} \]