A car is traveling at 20.0m/s and accelerates at 3.00m/s^2 to pass a truck. It takes 15.0 m to pass the truck. How fast is the car traveling after going 15.0 m. 490.m/s 110.m/s 22.1m/s 10.5m/s

To solve this problem, we can use the kinematic equation that relates initial velocity, acceleration, distance, and final velocity:<br /><br />v^2 = u^2 + 2as<br /><br />Where:<br />v = final velocity<br />u = initial velocity<br />a = acceleration<br />s = distance<br /><br />Given information:<br />- Initial velocity (u) = 20.0 m/s<br />- Acceleration (a) = 3.00 m/s^2<br />- Distance (s) = 15.0 m<br /><br />Substituting the values in the equation:<br /><br />v^2 = (20.0 m/s)^2 + 2 × (3.00 m/s^2) × (15.0 m)<br />v^2 = 400 m^2/s^2 + 90 m^2/s^2<br />v^2 = 490 m^2/s^2<br />v = √(490 m^2/s^2)<br />v = 22.1 m/s<br /><br />Therefore, the car is traveling at 22.1 m/s after going 15.0 m.<br /><br />The correct answer is 22.1 m/s.