4. A stevedore slides a crate along a dock with a 50 kg horizontal force of 175 N. The opposing force of friction is 120 N . If started from rest.what is the crate 's final velocity after 0.5 s?

To find the crate's final velocity, we can use Newton's second law and the kinematic equations. First, calculate the net force acting on the crate:<br /><br />\[ F_{\text{net}} = F_{\text{applied}} - F_{\text{friction}} = 175 \, \text{N} - 120 \, \text{N} = 55 \, \text{N} \]<br /><br />Next, use Newton's second law to find the acceleration of the crate:<br /><br />\[ F_{\text{net}} = m \cdot a \]<br /><br />\[ a = \frac{F_{\text{net}}}{m} = \frac{55 \, \text{N}}{50 \, \text{kg}} = 1.1 \, \text{m/s}^2 \]<br /><br />Now, use the kinematic equation to find the final velocity \( v \) after time \( t = 0.5 \, \text{s} \), starting from rest (\( u = 0 \)):<br /><br />\[ v = u + a \cdot t \]<br /><br />\[ v = 0 + (1.1 \, \text{m/s}^2) \cdot (0.5 \, \text{s}) \]<br /><br />\[ v = 0.55 \, \text{m/s} \]<br /><br />The crate's final velocity after 0.5 seconds is 0.55 m/s.