6. Sodium chloride is produced from its elements through a synthesis reaction. 2Na(s)+Cl_(2(g))arrow 2NaCl_((s)) Calculate the mass of each reactant would be required to produce 25,0 mol d sodium chloride.

To calculate the mass of each reactant required to produce 25.0 mol of sodium chloride (NaCl), we need to use stoichiometry based on the balanced chemical equation:<br /><br />\[ 2 \mathrm{Na}(s) + \mathrm{Cl}_2(g) \rightarrow 2 \mathrm{NaCl}(s) \]<br /><br />From the equation, we see that 2 moles of Na react with 1 mole of Cl\(_2\) to produce 2 moles of NaCl.<br /><br />First, determine the moles of each reactant needed to produce 25.0 moles of NaCl:<br />- Since 2 moles of Na produce 2 moles of NaCl, 25.0 moles of NaCl will require 25.0 moles of Na.<br />- Since 1 mole of Cl\(_2\) produces 2 moles of NaCl, 25.0 moles of NaCl will require 12.5 moles of Cl\(_2\).<br /><br />Next, convert the moles of each reactant to grams using their molar masses:<br />- Molar mass of Na = 22.99 g/mol<br />- Molar mass of Cl\(_2\) = 70.90 g/mol<br /><br />Calculate the mass of Na:<br />\[ \text{Mass of Na} = 25.0 \, \text{mol} \times 22.99 \, \text{g/mol} = 574.75 \, \text{g} \]<br /><br />Calculate the mass of Cl\(_2\):<br />\[ \text{Mass of Cl}_2 = 12.5 \, \text{mol} \times 70.90 \, \text{g/mol} = 886.25 \, \text{g} \]<br /><br />Therefore, to produce 25.0 moles of sodium chloride, you would need:<br />- 574.75 grams of sodium (Na)<br />- 886.25 grams of chlorine gas (Cl\(_2\))