PCl_(5)+underline ( )H_(2)Oarrow underline ( )HCl+H_(3)PO_(4) What coefficients would be needed to balance the above equation? 4.5 3,8 1.6 2.2

To balance the chemical equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.<br /><br />Given equation: $PCl_{5} + \underline{\quad}H_{2}O \rightarrow \underline{\quad}HCl + H_{3}PO_{4}$<br /><br />Let's start by balancing the chlorine (Cl) atoms. There are 5 chlorine atoms in $PCl_{5}$, so we need 5 chlorine atoms on the product side. This means we need 5 molecules of $HCl$.<br /><br />Now, let's balance the hydrogen (H) atoms. There are 5 chlorine atoms in $HCl$, so we have a total of 5 hydrogen atoms on the product side. To balance the hydrogen atoms, we need 5 molecules of $H_{2}O$ on the reactant side.<br /><br />Finally, let's balance the phosphorus (P) atoms. There is 1 phosphorus atom in $PCl_{5}$ and 1 phosphorus atom in $H_{3}PO_{4}$. So, the phosphorus atoms are already balanced.<br /><br />Now, let's rewrite the balanced equation:<br /><br />$PCl_{5} + 5H_{2}O \rightarrow 5HCl + H_{3}PO_{4}$<br /><br />Therefore, the coefficients needed to balance the equation are 1, 5, 5, and 1.