For the following unbalanced equation, what type of reaction is C_(5)H_(12)+O_(2)arrow H_(2)O+CO_(2) ? synthesis combustion decomposition single replacement double replacement

## Step 1<br />The given chemical equation is \(C_{5}H_{12}+O_{2}\rightarrow H_{2}O+CO_{2}\). This equation represents a reaction where a hydrocarbon (in this case, pentane, \(C_{5}H_{12}\)) reacts with oxygen (\(O_{2}\)) to produce water (\(H_{2}O\)) and carbon dioxide (\(CO_{2}\)).<br /><br />## Step 2<br />This type of reaction is known as a combustion reaction. Combustion reactions are characterized by the burning of a substance in the presence of oxygen, which results in the formation of water and carbon dioxide.<br /><br />## Step 3<br />The other options provided, such as synthesis, decomposition, single replacement, and double replacement, do not accurately describe this reaction. Synthesis reactions involve the combination of two or more simple substances to form a more complex substance. Decomposition reactions involve the breakdown of a complex substance into two or more simpler substances. Single replacement reactions involve one element being replaced by another in a compound. Double replacement reactions involve the exchange of ions between two compounds.