2. What mass of potassium (K) would produce 156 g of potassium chloride (KCU)? Cla k Write your path: 156gKLtimes (1molKL)/(244.55gKCl)times (2)/(2molKCl)times (341.10gK)/(1molK)=(10,639Ktimes 2)/(1449.1)

## Step 1<br />The problem involves stoichiometry, which is a branch of chemistry that deals with the quantitative relationships between reactants and products in a chemical reaction. The problem provides the mass of potassium chloride (KCl) and asks for the mass of potassium (K) that would produce this amount.<br /><br />## Step 2<br />The molar mass of KCl is given as 74.55 g/mol. This means that 1 mole of KCl has a mass of 74.55 g.<br /><br />## Step 3<br />The molar mass of K is given as 39.10 g/mol. This means that 1 mole of K has a mass of 39.10 g.<br /><br />## Step 4<br />The stoichiometry of the reaction between K and KCl is 1:1. This means that 1 mole of K reacts with 1 mole of KCl to produce 1 mole of KCl.<br /><br />## Step 5<br />Given that 1 mole of KCl has a mass of 74.55 g, we can calculate the number of moles of KCl in 156 g by dividing the mass of KCl by the molar mass of KCl.<br /><br />### \( \frac{156 g}{74.55 g/mol} = 2.1 mol \)<br /><br />## Step 6<br />Since the stoichiometry of the reaction is 1:1, the number of moles of K required is also 2.1 mol.<br /><br />## Step 7<br />Finally, we can calculate the mass of K required by multiplying the number of moles of K by the molar mass of K.<br /><br />### \( 2.1 mol \times 39.10 g/mol = 81.9 g \)