3Ta2S5+10BkAsarrow 5Bk2S3+2Ta3As5 How many moles of Ta3As5 dc I get from 12 mol Ta2S5? 2 4 6 8

To determine how many moles of \( \text{Ta}_3\text{As}_5 \) are produced from 12 moles of \( \text{Ta}_2\text{S}_5 \), we need to use the stoichiometric coefficients from the balanced chemical equation:<br /><br />\[ 3\text{Ta}_2\text{S}_5 + 10\text{BkAs} \rightarrow 5\text{Bk}_2\text{S}_3 + 2\text{Ta}_3\text{As}_5 \]<br /><br />From the equation, we see that 3 moles of \( \text{Ta}_2\text{S}_5 \) produce 2 moles of \( \text{Ta}_3\text{As}_5 \).<br /><br />We can set up a proportion to find out how many moles of \( \text{Ta}_3\text{As}_5 \) are produced from 12 moles of \( \text{Ta}_2\text{S}_5 \):<br /><br />\[ \frac{3 \text{ moles of } \text{Ta}_2\text{S}_5}{2 \text{ moles of } \text{Ta}_3\text{As}_5} = \frac{12 \text{ moles of } \text{Ta}_2\text{S}_5}{x \text{ moles of } \text{Ta}_3\text{As}_5} \]<br /><br />Solving for \( x \):<br /><br />\[ x = \frac{12 \times 2}{3} = 8 \]<br /><br />Therefore, 8 moles of \( \text{Ta}_3\text{As}_5 \) are produced from 12 moles of \( \text{Ta}_2\text{S}_5 \).<br /><br />So, the correct answer is:<br /><br />8