Question 20 (1 point) v=(m1v1+m2v2)/(m1+m2) A 2kg object moving at 5m/s collides head-on with a stationary 3kg object. If the collision is perfectly inelastic (objects stick together), what is the final velocity of the combined system? 2m/s 5m/s 10m/s d 3.5m/s

## Step 1: <br />Identify the given values:<br />- Mass of the first object, \( m_1 = 2 \, \text{kg} \)<br />- Velocity of the first object, \( v_1 = 5 \, \text{m/s} \)<br />- Mass of the second object, \( m_2 = 3 \, \text{kg} \)<br />- Velocity of the second object, \( v_2 = 0 \, \text{m/s} \) (since it is stationary)<br /><br />## Step 2:<br />Apply the conservation of momentum formula for a perfectly inelastic collision:<br />### \[ v = \frac{m_1 v_1 + m_2 v_2}{m_1 + m_2} \]<br /><br />## Step 3:<br />Substitute the given values into the formula:<br />### \[ v = \frac{(2 \, \text{kg} \times 5 \, \text{m/s}) + (3 \, \text{kg} \times 0 \, \text{m/s})}{2 \, \text{kg} + 3 \, \text{kg}} \]<br /><br />## Step 4:<br />Calculate the final velocity:<br />### \[ v = \frac{10 \, \text{kg} \cdot \text{m/s}}{5 \, \text{kg}} = 2 \, \text{m/s} \]