Two 10 ohms resistors are connected in series to a 12 V battery. Calculate the voltage drop and current across one of the 10 Ohm resistor 6 V, 0.6 A 8V, 0.6 A 1.2V,2 A 12V.12 A

To solve this problem, we need to use Ohm's Law and the concept of series circuits.<br /><br />Given information:<br />- Two 10 ohms resistors are connected in series to a 12 V battery.<br /><br />Step 1: Calculate the total resistance in the series circuit.<br />Total resistance = R1 + R2 = 10 ohms + 10 ohms = 20 ohms<br /><br />Step 2: Calculate the current flowing through the circuit.<br />Current (I) = Voltage (V) / Total resistance (R)<br />I = 12 V / 20 ohms = 0.6 A<br /><br />Step 3: Calculate the voltage drop across one of the 10 ohm resistors.<br />Voltage drop (V) = Current (I) × Resistance (R)<br />V = 0.6 A × 10 ohms = 6 V<br /><br />Therefore, the voltage drop across one of the 10 ohm resistors is 6 V, and the current flowing through the resistor is 0.6 A.<br /><br />The correct answer is:<br />6 V, 0.6 A