3Ta2S5+10BkAs-gt 5Bk2S3+2Ta3As5 How many moles of Ta3As5 do 5 points I get from 12 mol Ta2S5? 2 4 6 8

To determine how many moles of \( \text{Ta}_3\text{As}_5 \) are produced from 12 moles of \( \text{Ta}_2\text{S}_5 \), we need to use stoichiometry based on the balanced chemical equation:<br /><br />\[ 3\text{Ta}_2\text{S}_5 + 10\text{BkAs} \rightarrow 5\text{Bk}_2\text{S}_3 + 2\text{Ta}_3\text{As}_5 \]<br /><br />From the equation, we see that 3 moles of \( \text{Ta}_2\text{S}_5 \) produce 2 moles of \( \text{Ta}_3\text{As}_5 \).<br /><br />First, find the mole ratio between \( \text{Ta}_2\text{S}_5 \) and \( \text{Ta}_3\text{As}_5 \):<br /><br />\[ \frac{2 \text{ moles of } \text{Ta}_3\text{As}_5}{3 \text{ moles of } \text{Ta}_2\text{S}_5} \]<br /><br />Now, use this ratio to find out how many moles of \( \text{Ta}_3\text{As}_5 \) are produced from 12 moles of \( \text{Ta}_2\text{S}_5 \):<br /><br />\[ \text{Moles of } \text{Ta}_3\text{As}_5 = 12 \text{ moles of } \text{Ta}_2\text{S}_5 \times \frac{2 \text{ moles of } \text{Ta}_3\text{As}_5}{3 \text{ moles of } \text{Ta}_2\text{S}_5} \]<br /><br />\[ \text{Moles of } \text{Ta}_3\text{As}_5 = 8 \text{ moles} \]<br /><br />So, 8 moles of \( \text{Ta}_3\text{As}_5 \) are produced from 12 moles of \( \text{Ta}_2\text{S}_5 \).<br /><br />The correct answer is:<br />8