7) For each of the following , determine the type of bond (ionic polar covalent or nonpolar covalent) that should form betweer each pair of atoms. a) Se and S b) S and O c) Na and F d) land H

## Step 1<br />The type of bond that forms between two atoms is determined by the difference in their electronegativities. Electronegativity is a measure of the tendency of an atom to attract a bonding pair of electrons. The greater the difference in electronegativity, the more ionic the bond is.<br /><br />## Step 2<br />### **Ionic Bond**: <br />This bond forms when one atom donates an electron to another atom. This usually happens between a metal and a non-metal.<br /><br />## Step 3<br />### **Polar Covalent Bond**: <br />This bond forms when two atoms share a pair of electrons unequally. This usually happens between two non-metals.<br /><br />## Step 4<br />### **Nonpolar Covalent Bond**: <br />This bond forms when two atoms share a pair of electrons equally. This usually happens between two identical atoms.<br /><br />## Step 5<br />a) Se and S: Both Se and S are non-metals and they are very close in electronegativity. Therefore, they will form a nonpolar covalent bond.<br /><br />## Step 6<br />b) S and O: S and O are also non-metals but O is more electronegative than S. Therefore, they will form a polar covalent bond.<br /><br />## Step 7<br />c) Na and F: Na is a metal and F is a non-metal. Therefore, they will form an ionic bond.<br /><br />## Step 8<br />d) I and H: I is a non-metal and H is a non-metal. Therefore, they will form a polar covalent bond.