2. Find the molar mass of Mg_(3)(PO_(4))_(2)

To find the molar mass of \( Mg_3(PO_4)_2 \), we need to sum the molar masses of all the atoms in the compound. The compound consists of:<br /><br />- Magnesium (Mg)<br />- Phosphorus (P)<br />- Oxygen (O)<br /><br />The molar masses of these elements are approximately:<br />- Mg: 24.305 g/mol<br />- P: 30.9738 g/mol<br />- O: 16.00 g/mol<br /><br />The formula \( Mg_3(PO_4)_2 \) indicates:<br />- 3 magnesium atoms<br />- 2 phosphate groups (\( PO_4 \))<br /><br />Each phosphate group (\( PO_4 \)) consists of:<br />- 1 phosphorus atom<br />- 4 oxygen atoms<br /><br />So, for \( Mg_3(PO_4)_2 \):<br />- Magnesium: \( 3 \times 24.305 \) g/mol<br />- Phosphorus: \( 2 \times 30.9738 \) g/mol<br />- Oxygen: \( 2 \times 4 \times 16.00 \) g/mol<br /><br />Now, let's calculate each part:<br /><br />1. Magnesium: \( 3 \times 24.305 = 72.915 \) g/mol<br />2. Phosphorus: \( 2 \times 30.9738 = 61.9476 \) g/mol<br />3. Oxygen: \( 2 \times 4 \times 16.00 = 128.00 \) g/mol<br /><br />Finally, sum these values to get the molar mass of \( Mg_3(PO_4)_2 \):<br /><br />\[ 72.915 + 61.9476 + 128.00 = 262.8626 \] g/mol<br /><br />Therefore, the molar mass of \( Mg_3(PO_4)_2 \) is approximately 262.86 g/mol.