(4) 7. For your first trial, find how many moles of sllver nitrate are present at the beginning. Show your work. square

To find the number of moles of silver nitrate (AgNO3) present at the beginning, we need to use the formula:<br /><br />Moles = Mass / Molar Mass<br /><br />Given information:<br />- Mass of silver nitrate (AgNO3) = 4.7 grams<br /><br />Step 1: Calculate the molar mass of silver nitrate (AgNO3).<br />Molar mass of AgNO3 = Molar mass of Ag + Molar mass of N + 3 × Molar mass of O<br />Molar mass of AgNO3 = 107 g/mol + 14.01 g/mol + 3 × 16.00 g/mol<br />Molar mass of AgNO3 = 169.88 g/mol<br /><br />Step 2: Calculate the number of moles of silver nitrate (AgNO3).<br />Moles of AgNO3 = Mass of AgNO3 / Molar Mass of AgNO3<br />Moles of AgNO3 = 4.7 g / 169.88 g/mol<br />Moles of AgNO3 = 0.0277 mol<br /><br />Therefore, the number of moles of silver nitrate (AgNO3) present at the beginning is 0.0277 mol.