Sam is twirling a ball at a velocity of 3.41m/s The string she is using is 2.62 m long. What is the centripetal acceleration of Sam's ball? square

The question is asking for the centripetal acceleration of the ball Sam is twirling. The formula for centripetal acceleration is given by $a = \frac{v^2}{r}$, where $v$ is the velocity and $r$ is the radius of the circular path. In this case, the velocity $v$ is $3.41m/s$ and the radius $r$ is the length of the string, which is $2.62m$. Substituting these values into the formula gives $a = \frac{(3.41m/s)^2}{2.62m}$. Calculating this gives a centripetal acceleration of approximately $0.66m/s^2$. Therefore, the centripetal acceleration of Sam's ball is $0.66m/s^2$.