A periodic wave with wavelength lambda =2m has speed v=4(m)/(s) What is the wave's frequency? Round answer to one significant digit. square Hz

To find the frequency of the wave, we can use the formula:<br /><br />\[ v = \lambda \cdot f \]<br /><br />where:<br />- \( v \) is the speed of the wave,<br />- \( \lambda \) is the wavelength,<br />- \( f \) is the frequency.<br /><br />Given:<br />- \( v = 4 \, \frac{m}{s} \)<br />- \( \lambda = 2 \, m \)<br /><br />We need to solve for \( f \):<br /><br />\[ f = \frac{v}{\lambda} \]<br /><br />Substitute the given values:<br /><br />\[ f = \frac{4 \, \frac{m}{s}}{2 \, m} \]<br /><br />\[ f = 2 \, \frac{1}{s} \]<br /><br />So, the frequency of the wave is \( 2 \, \text{Hz} \).<br /><br />Rounded to one significant digit, the frequency is:<br /><br />\[ \boxed{2} \, \text{Hz} \]