If a sky diver jumps that weighs 90 N jumps out of a plane and pulls a parachute. He started falling at -9.8m/s/s and his acceleration slowed to 0m/s/s with the chute. What is the force of the chute up? 90 N 9.8m/s/s -9.8m/s/s ON

To find the force of the chute up, we can use Newton's second law of motion, which states that the force exerted on an object is equal to the mass of the object multiplied by its acceleration.<br /><br />First, let's find the mass of the skydiver. We know that the weight of the skydiver is 90 N, and weight is equal to mass multiplied by the acceleration due to gravity (9.8 m/s^2). Therefore, we can calculate the mass of the skydiver as follows:<br /><br />mass = weight / acceleration due to gravity<br />mass = 90 N / 9.8 m/s^2<br />mass ≈ 9.18 kg<br /><br />Next, we can calculate the force of the chute up using the formula:<br /><br />force = mass * acceleration<br /><br />Since the acceleration of the skydiver with the chute is 0 m/s^2, the force of the chute up is:<br /><br />force = 9.18 kg * 0 m/s^2<br />force = 0 N<br /><br />Therefore, the force of the chute up is 0 N.