16Ga+3S8-gt 8Ga2S3 How many moles of Ga2S3 do I get from 4 mol Ga and 4.5 mol S8 2 4 8 12

To determine how many moles of Ga2S3 are produced from 4 moles of Ga and 4.5 moles of S8, we need to use stoichiometry based on the balanced chemical equation:<br /><br />\[ 16Ga + 3S8 \rightarrow 8Ga2S3 \]<br /><br />First, identify the limiting reactant by comparing the mole ratio of the reactants to the stoichiometric ratio in the balanced equation.<br /><br />1. Calculate the stoichiometric ratio of Ga to S8:<br /> - According to the balanced equation, 16 moles of Ga react with 3 moles of S8.<br /> - Therefore, the stoichiometric ratio of Ga to S8 is \( \frac{16}{3} \).<br /><br />2. Compare the actual mole ratio of Ga to S8:<br /> - Given: 4 moles of Ga and 4.5 moles of S8.<br /> - Calculate the actual ratio: \( \frac{4 \text{ moles of Ga}}{4.5 \text{ moles of S8}} = \frac{8}{9} \).<br /><br />3. Determine the limiting reactant:<br /> - The actual ratio \( \frac{8}{9} \) is less than the stoichiometric ratio \( \frac{16}{3} \).<br /> - This indicates that Ga is the limiting reactant because there is less Ga available than required for the given amount of S8.<br /><br />4. Calculate the moles of Ga2S3 produced:<br /> - According to the balanced equation, 16 moles of Ga produce 8 moles of Ga2S3.<br /> - Therefore, 4 moles of Ga will produce \( \frac{8}{16} \times 4 = 2 \) moles of Ga2S3.<br /><br />Thus, from 4 moles of Ga and 4.5 moles of S8, you get 2 moles of Ga2S3.<br /><br />The correct answer is: 2