4HfP+3Ru(SO3)2arrow 2Hf2(SO3)3+Ru3P4 How many moles of Ru3P4 do I get from 0.66 mol Ru(SO3)2 0.22 0.66 0.99 1.98

To determine the number of moles of \( Ru_3P_4 \) produced from 0.66 moles of \( Ru(SO_3)_2 \), we need to use stoichiometry based on the balanced chemical equation:<br /><br />\[ 4HfP + 3Ru(SO_3)_2 \rightarrow 2Hf_2(SO_3)_3 + Ru_3P_4 \]<br /><br />First, identify the mole ratio between(SO_3)_2 \) and \( Ru_3P_4 \) from the balanced equation. According to the equation, 3 moles of \( Ru(SO_3)_2 \) produce 1 mole of \( Ru_3P_4 \).<br /><br />Now, use this ratio to find the number of moles of \( Ru_3P \) produced from 0.66 moles of \( Ru(SO_3)_2 \):<br /><br />\[ \text{Moles of } Ru_3P_4 = \frac{\text{Moles of } Ru(SO_3)_2}{3} \]<br /><br />\[ \text{Moles of } Ru_3P_4 = \frac{0.66 \text{ moles}}{3} \]<br /><br />\[ \text{Moles of } Ru_3P_4 = 0.22 \text{ moles} \]<br /><br />Therefore, the number of moles of \( Ru_3P_4 \) produced from 0.66 moles of \( Ru(SO_3)_2 \) is 0.22 moles.<br /><br />So, the correct answer is:<br />\[ \boxed{0.22} \]