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Using the equation below,convert 15.03 grams of O_(2) to moles of KCI.Please round
your answer to two digits after the decimal point and don't forget units and
substance!
2KClO_(3)... 2KCl+3O_(2)
Your Answer:
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Answer
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Question point) Retake question Using the equation below,convert 15.03 grams of O_(2) to moles of KCI.Please round your answer to two digits after the decimal point and don't forget units and substance! 2KClO_(3)... 2KCl+3O_(2) Your Answer: square square Answer units
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### 0.31 mol KCl
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## Step1: Determine the Molar Mass of $O_2$<br />### Calculate the molar mass of $O_2$ using the atomic mass of oxygen (approximately 16.00 g/mol). The molar mass of $O_2$ is $32.00 \, \text{g/mol}$.<br /><br />## Step2: Convert Grams of $O_2$ to Moles<br />### Use the formula $\text{moles} = \frac{\text{mass}}{\text{molar mass}}$. For $15.03 \, \text{g}$ of $O_2$, the moles are calculated as $\frac{15.03}{32.00} \approx 0.469 \, \text{mol}$.<br /><br />## Step3: Use Stoichiometry to Find Moles of KCl<br />### From the balanced equation $2KClO_{3} \rightarrow 2KCl + 3O_{2}$, the mole ratio between $O_2$ and $KCl$ is $3:2$. Therefore, for every 3 moles of $O_2$, there are 2 moles of $KCl$. Calculate moles of $KCl$ as follows: $0.469 \times \frac{2}{3} \approx 0.313 \, \text{mol}$.
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