How fast will a 750kg car go if it uses 300,000W of power to accelerate from a speed of 10m/s for 5 seconds? (Hint find work first) W=F(Delta d) P=(WorE)/(t) W=Delta KE=1/2m(v_(f)^2-v_(i)^2) W=Delta PE=mg(h_(f)-h_(i)) WorE=Pt 60,000m/s 80m/s 160m/s 64m/s 8.94m/s

To solve this problem, we need to find the final velocity of the car after it accelerates for 5 seconds using 300,000W of power.<br /><br />Given information:<br />- Mass of the car: 750 kg<br />- Initial velocity: 10 m/s<br />- Power: 300,000 W<br />- Time: 5 seconds<br /><br />Step 1: Calculate the work done by the car.<br />Work done (W) = Change in kinetic energy<br />W = ΔKE = 1/2 m (vf^2 - vi^2)<br />W = 1/2 × 750 kg × (vf^2 - (10 m/s)^2)<br /><br />Step 2: Calculate the power.<br />Power (P) = Work done / Time<br />P = W / t<br />P = 1/2 × 750 kg × (vf^2 - (10 m/s)^2) / 5 s<br /><br />Step 3: Solve for the final velocity (vf).<br />300,000 W = 1/2 × 750 kg × (vf^2 - (10 m/s)^2) / 5 s<br />vf^2 = 160 m^2/s^2<br />vf = √(160 m^2/s^2)<br />vf = 12.65 m/s<br /><br />Therefore, the car will go at a speed of 12.65 m/s after accelerating for 5 seconds using 300,000W of power.