This question refers to the balanced equation below: 16HCl(aq)+2K_(2)Cr_(2)O_(7)(aq)+3CH_(3)OH(l)arrow 4CrCl_(3)(aq)+3CHO_(2)H(l)+4 KCl(aq)+11H_(2)O(l) What is the mole ratio of CH_(3)OH to HCl? Answer: square CH_(3)OH:square HCl

To determine the mole ratio of $CH_{3}OH$ to HCl, we need to look at the coefficients in the balanced chemical equation.<br /><br />The balanced equation is:<br />$16HCl(aq)+2K_{2}Cr_{2}O_{7}(aq)+3CH_{3}OH(l)\rightarrow 4CrCl_{3}(aq)+3CHO_{2}H(l)+4KCl(aq)+11H_{2}O(l)$<br /><br />From the equation, we can see that the coefficient for $CH_{3}OH$ is 3 and the coefficient for HCl is 16.<br /><br />Therefore, the mole ratio of $CH_{3}OH$ to HCl is 3:16.<br /><br />Answer: $CH_{3}OH:16HCl$