What is the percent composition of Bromine (Br)in CuBr_(2) Round your percent to 2 decimal places. square

To find the percent composition of Bromine (Br) in \( CuBr_2 \), we need to follow these steps:<br /><br />1. **Determine the molar masses of each element in the compound:**<br /> - Copper (Cu): The atomic mass of Cu is approximately 63.55 g/mol.<br /> - Bromine (Br): The atomic mass of Br is approximately 79.90 g/mol.<br /><br />2. **Calculate the molar mass of \( CuBr_2 \):**<br /> - The formula \( CuBr_2 \) indicates that there is 1 copper atom and 2 bromine atoms.<br /> - Molar mass of \( CuBr_2 \) = (1 × 63.55 g/mol) + (2 × 79.90 g/mol)<br /> - Molar mass of \( CuBr_2 \) = 63.55 g/mol + 159.80 g/mol<br /> - Molar mass of \( CuBr_2 \) = 223.35 g/mol<br /><br />3. **Calculate the total mass of bromine in the compound:**<br /> - Since there are 2 bromine atoms in \( CuBr_2 \):<br /> - Total mass of bromine = 2 × 79.90 g/mol = 159.80 g/mol<br /><br />4. **Calculate the percent composition of bromine:**<br /> - Percent composition of bromine = (Total mass of bromine / Molar mass of \( CuBr_2 \)) × 100%<br /> - Percent composition of bromine = (159.80 g/mol / 223.35 g/mol) × 100%<br /> - Percent composition of bromine ≈ 71.34%<br /><br />Therefore, the percent composition of Bromine (Br) in \( CuBr_2 \) is approximately 71.34%.