A 4.0 kg ball is thrown at 6m/s . What is the ball's momentum? a 18kgm/s b 24kgm/s C 6kgm/s d 12kgm/s Question 6 (1 point) A 12 kg brick is dropped and hits the ground at 9m/s . If it has an impact time of 0.005 seconds, with what force did it hit the ground? a 21600 N b 0.54 N C 0.0067 N d 108 N

Question 1:<br />The momentum of an object is calculated by multiplying its mass by its velocity. In this case, the mass of the ball is 4.0 kg and its velocity is 6 m/s. Therefore, the ball's momentum is:<br /><br />Momentum = mass x velocity<br />Momentum = 4.0 kg x 6 m/s<br />Momentum = 24 kgm/s<br /><br />So, the correct answer is b) 24 kgm/s.<br /><br />Question 2:<br />To find the force with which the brick hit the ground, we can use the formula:<br /><br />Force = Change in momentum / Time<br /><br />First, let's calculate the change in momentum. The initial momentum of the brick is 0 (since it is dropped), and the final momentum is 12 kg x 9 m/s = 108 kgm/s. Therefore, the change in momentum is 108 kgm/s.<br /><br />Now, we can calculate the force:<br /><br />Force = Change in momentum / Time<br />Force = 108 kgm/s / 0.005 s<br />Force = 21600 N<br /><br />So, the correct answer is a) 21600 N.