A gas occupies 100mL at a pressure of 789mm Hg. What is the volume of the gas when it's pressure is increased to 880mm Hg P_(1)V_(1)=P_(2)V_(2) 113mL 190mL 89mL

To solve this problem, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional, as long as the temperature remains constant. Mathematically, this can be expressed as:<br /><br />\[ P_1V_1 = P_2V_2 \]<br /><br />Given:<br />- \( P_1 = 789 \) mm Hg<br />- \( V_1 = 100 \) mL<br />- \( P_2 = 880 \) mm Hg<br /><br />We need to find \( V_2 \).<br /><br />Rearranging the equation to solve for \( V_2 \):<br /><br />\[ V_2 = \frac{P_1V_1}{P_2} \]<br /><br />Substituting the given values:<br /><br />\[ V_2 = \frac{789 \text{ mm Hg} \times 100 \text{ mL}}{880 \text{ mm Hg}} \]<br /><br />\[ V_2 = \frac{78900 \text{ mL} \cdot \text{mm Hg}}{880 \text{ mm Hg}} \]<br /><br />\[ V_2 \approx 89.66 \text{ mL} \]<br /><br />Rounding to the nearest whole number, the volume of the gas when the pressure is increased to 880 mm Hg is approximately 90 mL.<br /><br />Therefore, the correct answer is:<br />89mL