on a gas is at 3 Land 3 mol, what is the number of moles of the gas when volume changes to 15 L? 15 mol 45 mol 9.0 mol 6.0 mol

To solve this problem, we can use the ideal gas law, which states that the pressure, volume, and temperature of a gas are related by the equation PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.<br /><br />Given that the initial volume of the gas is 3 L and the initial number of moles is 3 mol, we can use the ideal gas law to find the initial pressure and temperature of the gas:<br /><br />PV = nRT<br />P(3 L) = (3 mol)(R)(T)<br />P = (3 mol)(R)(T)/(3 L)<br /><br />Now, we can use this equation to find the number of moles of the gas when the volume changes to 15 L:<br /><br />PV = nRT<br />P(15 L) = (n mol)(R)(T)<br />n = (P)(15 L)/(R)(T)<br /><br />Since the pressure and temperature of the gas remain constant, we can substitute the expression for P from the initial condition into this equation:<br /><br />n = ((3 mol)(R)(T)/(3 L))(15 L)/(R)(T)<br />n = 5 mol<br /><br />Therefore, the number of moles of the gas when the volume changes to 15 L is 5 mol.