C_(2)H_(4)+3O_(2)-2CO_(2)+2H_(2)O Using the equation for the complete combustion of ethene (C_(2)H_(4)) which will be the limiting reactant if equal masses of both ethene and oxygen are provided? Oxygen Not enough information is given. Neither is limiting. d Ethene

To determine the limiting reactant, we need to compare the mole ratio of ethene to oxygen in the balanced chemical equation.<br /><br />The balanced chemical equation for the complete combustion of ethene is:<br /><br />$C_{2}H_{4} + 3O_{2} \rightarrow 2CO_{2} + 2H_{2}O$<br /><br />From the equation, we can see that 1 mole of ethene reacts with 3 moles of oxygen to produce 2 moles of carbon dioxide and 2 moles of water.<br /><br />Now, let's compare the molar masses of ethene and oxygen:<br /><br />Molar mass of ethene (C2H4) = 2(12.01) + 4(1.01) = 28.05 g/mol<br />Molar mass of oxygen (O2) = 2(16.00) = 32.00 g/mol<br /><br />Since the molar mass of oxygen is greater than the molar mass of ethene, we can conclude that oxygen is the limiting reactant.<br /><br />Therefore, the correct answer is: Oxygen.