The following equation represents the reaction between solid aluminum and hydrochloric acid. Balance the equation by filling in the correct coefficients for each substance. square Al(s)+square HCl(aq)arrow square AlCl_(3)(aq)+square H_(2)(g)

To balance the chemical equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.<br /><br />Given equation: $\square Al(s)+\square HCl(aq)\rightarrow \square AlCl_{3}(aq)+\square H_{2}(g)$<br /><br />Step 1: Balance the aluminum atoms.<br />There is 1 aluminum atom on the left side and 1 aluminum atom on the right side. So, the coefficient for Al(s) is 1.<br /><br />Step 2: Balance the chlorine atoms.<br />There are 3 chlorine atoms in AlCl3 on the right side. To balance the, we need 3 HCl molecules on the left side. So, the coefficient for HCl(aq) is 3.<br /><br />Step 3: Balance the hydrogen atoms.<br />There are 2 hydrogen atoms in H2 on the right side. To balance the hydrogen atoms, we need 3 HCl molecules on the left side. So, the coefficient for H2(g) is 3/2.<br /><br />The balanced equation is:<br />$1 Al(s) + 3 HCl(aq) \rightarrow 1 AlCl_{3}(aq) + \frac{3}{2} H_{2}(g)$<br /><br />Therefore, the coefficients for each substance are:<br />$1 Al(s) + 3 HCl(aq) \rightarrow 1 AlCl_{3}(aq) + \frac{3}{2} H_{2}(g)$