What is the molar mass of (NH_(4))_(2)S' Use this Periodic Table and round your final answer to two decimals. square

To calculate the molar mass of $(NH_{4})_{2}S$, we need to find the molar masses of each element in the compound and then multiply them by the number of atoms of that element in the compound.<br /><br />The molar masses of the elements are:<br />- Nitrogen (N): 14.01 g/mol<br />- Hydrogen (H): 1.01 g/mol<br />- Sulfur (S): 32.07 g/mol<br /><br />Now, let's calculate the molar mass of $(NH_{4})_{2}S$:<br /><br />1. Calculate the molar mass of $NH_{4}$:<br /> - Nitrogen (N): 14.01 g/mol<br /> - Hydrogen (H): 1.01 g/mol<br /> - Total molar mass of $NH_{4}$ = 14.01 g/mol + (4 * 1.01 g/mol) = 18.05 g/mol<br /><br />2. Since there are two $NH_{4}$ groups in $(NH_{4})_{2}S$, we need to multiply the molar mass of $NH_{4}$ by 2:<br /> - Total molar mass of $(NH_{4})_{2}$ = 2 * 18.05 g/mol = 36.10 g/mol<br /><br />3. Add the molar mass of sulfur (S) to the total molar mass of $(NH_{4})_{2}$:<br /> - Total molar mass of $(NH_{4})_{2}S$ = 36.10 g/mol + 32.07 g/mol = 68.17 g/mol<br /><br />Therefore, the molar mass of $(NH_{4})_{2}S$ is 68.17 g/mol.