Given a gas is at 5 atm and 7 L,what is the pressure of the gas when volume changes to 25 L? 25 atm 7.0 atm 14 atm 4.1 atm

## Step 1<br />The problem involves Boyle's Law, which states that the pressure and volume of a gas have an inverse relationship when the temperature is held constant. This means that if the volume of the gas increases, the pressure decreases, and vice versa. <br /><br />## Step 2<br />The formula for Boyle's Law is given as:<br />### \(P1 \times V1 = P2 \times V2\)<br />where \(P1\) and \(V1\) are the initial pressure and volume, and \(P2\) and \(V2\) are the final pressure and volume.<br /><br />## Step 3<br />In this problem, the initial pressure \(P1\) is 5 atm, the initial volume \(V1\) is 7 L, and the final volume \(V2\) is 25 L. We are asked to find the final pressure \(P2\).<br /><br /> 4<br />We can rearrange the Boyle's Law formula to solve for \(P2\):<br />### \(P2 = \frac{P1 \times V1}{V2}\)<br /><br />## Step 5<br />Substitute the given values into the formula:<br />### \(P2 = \frac{5 \, \text{atm} \times 7 \, \text{L}}{25 \, \text{L}}\)<br /><br />## Step 6<br />Calculate the value of \(P2\).