5KNO3+Mnl5-gt Mn(NO3)5+5KI How many moles of Mn(NO3)5 do I get from 2 mol KNO3? 0.4 2 5 10

To determine how many moles of Mn(NO3)5 are produced from 2 moles of KNO3, we need to use the stoichiometry of the balanced chemical equation.<br /><br />The balanced chemical equation is:<br />$5KNO3 + MnCl5 \rightarrow Mn(NO3)5 + 5KI$<br /><br />From the equation, we can see that 5 moles of KNO3 are required to produce 1 mole of Mn(NO3)5.<br /><br />Given that we have 2 moles of KNO3, we can calculate the number of moles of Mn(NO3)5 produced as follows:<br /><br />Number of moles of Mn(NO3)5 = (2 moles of KNO3) / (5 moles of KNO3 per 1 mole of Mn(NO3)5)<br />Number of moles of Mn(NO3)5 = 0.4 moles<br /><br />Therefore, the correct answer is 0.4 moles of Mn(NO3)5.