This question refers to the balanced equation below: 6HCl(aq)+2K_(2)Cr_(2)O_(7)(aq)+3ClH_(3)OH(l)arrow 4ClCl_(3)(aq)+3ClO_(2)H(l)+4 KCl(aq)+11H_(2)O(l) What is the mole ratio of CH_(3)OH to CHO_(2)H Answer: square CH_(3)OH: square CHO_(2)H

To determine the mole ratio of $CH_{3}OH$ to $CHO_{2}H$, we need to look at the coefficients in the balanced chemical equation.<br /><br />The balanced equation is:<br />$6HCl(aq)+2K_{2}Cr_{2}O_{7}(aq)+3CH_{3}OH(l)\rightarrow 4CrCl_{3}(aq)+3CHO_{2}H(l)+4KCl(aq)+11H_{2}O(l)$<br /><br />From the equation, we can see that the coefficient for $CH_{3}OH$ is 3 and the coefficient for $CHO_{2}H$ is 3.<br /><br />Therefore, the mole ratio of $CH_{3}OH$ to $CHO_{2}H$ is 1:1.<br /><br />Answer: $CH_{3}OH: 1, CHO_{2}H: 1$