EuSe+2Tblarrow Eul2+Tb2Se How many grams of Eul2 do I get from 147.710 poi grams of EuSe? (Eu=152Se=79Tb=159I=127) 259 g 406 g 518g 635g

To solve this problem, we need to use the concept of stoichiometry and the molar masses of the compounds involved.<br /><br />Given information:<br />- The balanced chemical equation is: EuSe + 2TbI → EuI2 + Tb2Se<br />- The molar masses are: Eu = 152, Se = 79, Tb = 159, I = 127<br />- The mass of EuSe is 147.710 g<br /><br />Step 1: Calculate the molar mass of EuSe.<br />Molar mass of EuSe = 152 + 79 = 231 g/mol<br /><br />Step 2: Calculate the number of moles of EuSe.<br />Number of moles of EuSe = 147.710 g / 231 g/mol = 0.641 mol<br /><br />Step 3: Use the stoichiometry of the balanced equation to find the number of moles of EuI2.<br />According to the balanced equation, 1 mol of EuSe produces 1 mol of EuI2.<br />Number of moles of EuI2 = 0.: Calculate the molar mass of EuI2.<br />Molar mass of EuI2 = 152 + 2(127) = 406 g/mol<br /><br />Step 5: Calculate the mass of EuI2 produced.<br />Mass of EuI2 = 0.641 mol × 406 g/mol = 259.686 g<br /><br />Therefore, the correct answer is 259 g.