11. What are the coefficents when the following equation is balanced? underline ( )FeS_(2)+underline ( )O_(2)arrow underline ( )Fe_(2)O_(3)+underline ( )SO_(2) 2,6,1,4 2,5,2,4 4,8,2,6 4,11,2,8

To balance the chemical equation \(FeS_{2} + O_{2} \rightarrow Fe_{2}O_{3} + SO_{2}\), we need to ensure that the number of atoms of each element is the same on both sides of the equation.<br /><br />Let's start by writing down the number of atoms of each element in the unbalanced equation:<br /><br />\(FeS_{2} + O_{2} \rightarrow Fe_{2}O_{3} + SO_{2}\)<br /><br />On the left side:<br />- Fe: 1<br />- S: 2<br />- O: 2<br /><br />On the right side:<br />- Fe: 2<br />- S: 1<br />- O: 5<br /><br />To balance the equation, we need to adjust the coefficients in front of each compound.<br /><br />Let's start with the iron (Fe) atoms. We have 1 Fe atom on the left side and 2 Fe atoms on the right side. To balance the Fe atoms, we need to put a coefficient of 2 in front of \(FeS_{2}\):<br /><br />\(2FeS_{2} + O_{2} \rightarrow Fe_{2}O_{3} + SO_{2}\)<br /><br />Now let's move on to the sulfur (S) atoms. We have 2 S atoms on the left side and 1 S atom on the right side. To balance the S atoms, we need to put a coefficient of 2 in front of \(SO_{2}\):<br /><br />\(2FeS_{2} + O_{2} \rightarrow Fe_{2}O_{3} + 2SO_{2}\)<br /><br />Finally, let's balance the oxygen (O) atoms. We have 2 O atoms on the left side and 7 O atoms on the right side (3 from \(Fe_{2}O_{3}\) and 4 from \(2SO_{2}\)). To balance the O atoms, we need to put a coefficient of 4 in front of \(O_{2}\):<br /><br />\(2FeS_{2} + 4O_{2} \rightarrow Fe_{2}O_{3} + 2SO_{2}\)<br /><br />Now the equation is balanced, and we can see that the coefficients are:<br />- \(FeS_{2}\): 2<br />- \(O_{2}\): 4<br />- \(Fe_{2}O_{3}\): 1<br />- \(SO_{2}\): 2<br /><br />Therefore, the correct answer is \(2, 4, 1, 2\).