The chemical equation below is unbalanced. Al(OH)_(3)+H_(2)SO_(4)arrow Al_(2)(SO_(4))_(3)+H_(2)O What is the coefficient of H_(2)O when the equation is correctly balanced using the smallest whole-number coefficients? A. 2 B. 3 C. 4 D. 6

To balance the chemical equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.<br /><br />Let's start by balancing the aluminum atoms. We have 1 aluminum atom on the left side and 2 aluminum atoms on the right side. To balance the aluminum atoms, we need to put a coefficient of 2 in front of $Al(OH)_{3}$ on the left side.<br /><br />$2Al(OH)_{3}+H_{2}SO_{4}\rightarrow Al_{2}(SO_{4})_{3}+H_{2}O$<br /><br />Next, let's balance the sulfur atoms. We have 1 sulfur atom on the left side and 3 sulfur atoms on the right side. To balance the sulfur atoms, we need to put a coefficient of 3 in front of $H_{2}SO_{4}$ on the left side.<br /><br />$2Al(OH)_{3}+3H_{2}SO_{4}\rightarrow Al_{2}(SO_{4})_{3}+H_{2}O$<br /><br />Finally, let's balance the oxygen atoms. We have 6 oxygen atoms on the left side and 12 oxygen atoms on the right side. To balance the oxygen atoms, we need to put a coefficient of 6 in front of $H_{2}O$ on the right side.<br /><br />$2Al(OH)_{3}+3H_{2}SO_{4}\rightarrow Al_{2}(SO_{4})_{3}+6H_{2}O$<br /><br />Therefore, the coefficient of $H_{2}O$ when the equation is correctly balanced using the smallest whole-number coefficients is 6.<br /><br />The correct answer is D. 6.