Some dry chemicals can be used to put out forest fires. Sodium hydrogen carbonato is ane such chamical that upon having decomposas into dioxidu to suffocate the fire as shown in the balanced chemical reaction below. 2NaHCO_(3)(s)xrightarrow (Delta )Na_(2)CO_(3)(s)+H_(2)O(g)+CO_(2)(g). Determine the number of moles of Sodium hydrogen carbonate docomposad to produced 7.0 meles at carbon dioxide gas 3.5 moles 7.0 males 14 moles none of the ahove POSSIBLE POINTS: 12:

To determine the number of moles of sodium hydrogen carbonate (\(NaHCO_3\)) decomposed to produce 7.0 moles of carbon dioxide (\(CO_2\)), we can use the stoichiometry of the balanced chemical equation:<br /><br />\[ 2 \, \text{moles of } NaHCO_3 \rightarrow 1 \, \text{mole of } CO_2 \]<br /><br />According to the equation, 2 moles of \(NaHCO_3\) produce 1 mole of \(CO_2\). Therefore, to produce 7.0 moles of \(CO_2\), you need:<br /><br />\[ 7.0 \, \text{moles of } CO_2 \times \frac{2 \, \text{moles of } NaHCO_3}{1 \, \text{mole of } CO_2} = 14 \, \text{moles of } NaHCO_3 \]<br /><br />So, the correct answer is 14 moles.