Water is sometimes removed from the products of a reaction by placing the products in a closed container with excess P_(4)O_(10) Water is absorbed by the following reaction. P_(4)O_(10)+6H_(2)Oarrow 4H_(3)PO_(4) What is the mole ratio of water to H_(3)PO_(4)?Donot simplify the ratio. H_(2)O:H_(3)PO_(4)=square :4 DOM: 19

To determine the mole ratio of water ($H_2O$) to $H_3PO_4$, we need to look at the balanced chemical equation provided:<br /><br />\[ P_4O_{10} + 6H_2O \rightarrow 4H_3PO_4 \]<br /><br />From this equation, we can see that 6 moles of water ($H_2O$) are required to react with 1 mole of $P_4O_{10}$ to produce 4 moles of $H_3PO_4$.<br /><br />Therefore, the mole ratio of water to $H_3PO_4$ is:<br /><br />\[ H_2O : H_3PO_4 = 6 : 4 \]<br /><br />So, the answer is:<br /><br />\[ H_2O : H_3PO_4 = 6 : 4 \]