Balance the following equation: square CaCl_(2)+square Na_(3)PO_(4)arrow square Ca_(3)(PO_(4))_(2)+square NaCl

To balance the chemical equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.<br /><br />The unbalanced equation is:<br />\[ \square CaCl_{2} + \square Na_{3}PO_{4} \rightarrow \square Ca_{3}(PO_{4})_{2} + \square NaCl \]<br /><br />Let's start by balancing the calcium (Ca) atoms. There are 3 calcium atoms in \( Ca_{3}(PO_{4})_{2} \), so we need 3 calcium atoms on the left side:<br />\[ 3CaCl_{2} + \square Na_{3}PO_{4} \rightarrow Ca_{3}(PO_{4})_{2} + \square NaCl \]<br /><br />Next, let's balance the phosphate (PO₄) groups. There are 2 phosphate groups in \( Ca_{3}(PO_{4})_{2} \), so we need 2 sodium phosphate molecules on the left side:<br />\[ 3CaCl_{2} + 2Na_{3}PO_{4} \rightarrow Ca_{3}(PO_{4})_{2} + \square NaCl \]<br /><br />Finally, let's balance the sodium (Na) and chlorine (Cl) atoms. There are 6 sodium atoms on the left side (from 2 \( Na_{3}PO_{4} \)), so we need 6 sodium atoms on the right side. Similarly, there are 6 chlorine atoms on the left side (from 3 \( CaCl_{2} \)), so we need 6 chlorine atoms on the right side:<br />\[ 3CaCl_{2} + 2Na_{3}PO_{4} \rightarrow Ca_{3}(PO_{4})_{2} + 6NaCl \]<br /><br />Now the equation is balanced:<br />\[ 3CaCl_{2} + 2Na_{3}PO_{4} \rightarrow Ca_{3}(PO_{4})_{2} + 6NaCl \]<br /><br />So, the balanced equation is:<br />\[ 3CaCl_{2} + 2Na_{3}PO_{4} \rightarrow Ca_{3}(PO_{4})_{2} + 6NaCl \]