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
Given a ga s is at 24 Land 349 K what is the volume of the gas when temperature changes to 300 K? 10.3 L 60.01 120L 20.6 L
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The final volume of the gas when the temperature changes to 300 K is approximately 20.6 L.
Explicar
## Step 1<br />The problem involves the application of Charles's Law, which states that the volume of a gas is directly proportional to its temperature, provided the pressure and the amount of gas remain constant. This relationship can be mathematically represented as:<br />### \( \frac{V1}{T1} = \frac{V2}{T2} \)<br />where \( V1 \) and \( T1 \) are the initial volume and temperature, and \( V2 \) and \( T2 \) are the final volume and temperature.<br /><br />## Step 2<br />In this problem, the initial volume \( V1 \) is 24 L, the initial temperature \( T1 \) is 349 K, and the final temperature \( T2 \) is 300 K. We are asked to find the final volume \( V2 \).<br /><br />## Step 3<br />We can rearrange the formula to solve for \( V2 \):<br />### \( V2 = V1 \times \frac{T2}{T1} \)<br /><br />## Step 4<br />Substitute the given values into the formula:<br />### \( V2 = 24 \times \frac{300}{349} \)<br /><br />## Step 5<br />Calculate the value of \( V2 \).
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