The equation shows reactants to a neutralization Which describes what will happen to the Hi- reaction. Ca^2++OH^-+H^++NO_(3)^-arrow Which describes what will happen to the H+ when these reactants form products? H^+ binds with NO_(3)^- to make a salt. H^+ binds with Ca^2+ to make an acid. H^+ binds with OH^- to make water. H^+ binds with Ca^2+ to make a base.

In a neutralization reaction, an acid reacts with a base to form a salt and water. The given equation is a representation of such a reaction. In this reaction, $Ca^{2+}$ is a calcium ion, $OH^{-}$ is a hydroxide ion, $H^{+}$ is a hydrogen ion, and $NO_{3}^{-}$ is a nitrate ion. When these reactants combine, the hydrogen ion ($H^{+}$) will bind with the hydroxide ion ($OH^{-}$) to form water ($H_{2}O$). This is a typical neutralization reaction where an acid (represented by $H^{+}$) reacts with a base (represented by $OH^{-}$) to produce water. The other options provided do not correctly describe the reaction of $H^{+}$ in this context. $H^{+}$ does not bind with $NO_{3}^{-}$ to make a salt, nor does it bind with $Ca^{2+}$ to make an acid or a base. Therefore, the correct description of what will happen to the $H^{+}$ when these reactants form products is that it will bind with $OH^{-}$ to make water.