Question 9 (1 point) A hunter uses a blowgun to hunt for supper. A force of 2.0 Newtons is applied to a 0.05- kilogram dart for 075 seconds. The speed of the dart as it leaves the blowgun is about: p=mv J=Ft=mDelta v m_(1)v_(1i)+m_(2)v_(2i)=m_(1)v_(1f)+m_(2)v_(2f) a 30m/sec b 0.13m/sec C 1.5m/sec d 300m/sec

## Step 1<br />The problem involves the calculation of the speed of a dart as it leaves a blowgun. The force applied to the dart is 2.0 Newtons, the mass of the dart is 0.05 kilograms, and the time for which the force is applied is 0.75 seconds. We can use the formula for impulse, which is the product of force and time, to find the change in momentum of the dart.<br /><br />### **Impulse = Force x Time**<br /><br />## Step 2<br />The impulse experienced by the dart is equal to the change in momentum of the dart. The formula for momentum is mass times velocity.<br /><br />### **Momentum = Mass x Velocity**<br /><br />## Step 3<br />We can rearrange the formula for momentum to solve for velocity.<br /><br />### **Velocity = Momentum / Mass**<br /><br />## Step 4<br />Substitute the given values into the formula for velocity.<br /><br />### **Velocity = (Force x Time) / Mass**<br /><br />## Step 5<br />Calculate the velocity.<br /><br />### **Velocity = (2.0 N x 0.75 s) / 0.05 kg = 30 m/s**