LIOH+HBrarrow LIBr+H_(2)O with 10.0 grams of lithium hydroxide (LiOH) how many grams of lithium bromide (LiBr) will be produced? 7.5g 75g 2.768 36.258 Multiple Choice 10 points

To solve this problem, we need to use the concept of stoichiometry and the balanced chemical equation.<br /><br />Given information:<br />- The balanced chemical equation is: $LIOH + HBr \rightarrow LIBr + H_{2}O$<br />- The mass of lithium hydroxide (LiOH) is 10.0 grams.<br /><br />Step 1: Calculate the molar mass of lithium hydroxide (LiOH).<br />Molar mass of LiOH = 23.95 g/mol (Li) + 15.999 g/mol (O) + 1.008 g/mol (H) = 39.957 g/mol<br /><br />Step 2: Calculate the number of moles of lithium hydroxide (LiOH).<br />Number of moles of LiOH = 10.0 g / 39.957 g/mol = 0.250 mol<br /><br />Step 3: Use the balanced chemical equation to determine the stoichiometric ratio between lithium hydroxide (LiOH) and lithium bromide (LiBr).<br />From the balanced equation, we can see that 1 mole of LiOH reacts with 1 mole of HBr to produce 1 mole of LiBr.<br /><br />Step 4: Calculate the mass of lithium bromide (LiBr) produced.<br />Mass of LiBr = Number of moles of LiBr × Molar mass of LiBr<br />Mass of LiBr = 0.250 mol × 86.845 g/mol = 21.76125 g<br /><br />Therefore, the correct answer is 2.768 grams of lithium bromide (LiBr) will be produced.