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C_(4)H_(10)+O_(2)arrow CO_(2)+H_(2)O c.

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C_(4)H_(10)+O_(2)arrow CO_(2)+H_(2)O
c.

C_(4)H_(10)+O_(2)arrow CO_(2)+H_(2)O c.

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Luzmaestro · Tutor durante 5 años
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C4H10 + 6.5O2 → 4CO2 + 5H2O

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The question is asking for the balanced chemical equation for the reaction of butane (C4H10) with oxygen (O2) to produce carbon dioxide (CO2) and water (H2O). To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation. <br /><br />Starting with carbon, we have 4 carbon atoms in butane, so we need 4 carbon dioxide molecules on the product side. This gives us 4 carbon atoms on both sides. <br /><br />Next, we look at hydrogen. We have 10 hydrogen atoms in butane, so we need 5 water molecules on the product side to balance the hydrogen atoms. This gives us 10 hydrogen atoms on both sides. <br /><br />Finally, we look at oxygen. We have 4 carbon dioxide molecules and 5 water molecules on the product side, which gives us a total of 13 oxygen atoms. To balance the oxygen atoms, we need 13/2 = 6.5 oxygen molecules on the reactant side. <br /><br />Therefore, the balanced chemical equation is: C4H10 + 6.5O2 → 4CO2 + 5H2O.
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